How does scala decide on precedence when methods are used in operator notation, like 2 + 2 * 7 ? What is Scala's default rule here?
Answer
Scala decides precedence based on the first character of the methods used in operator notation (this rule has exceptions). If the method name starts with a *, for example, it will have a higher precedence than a method that starts with a +.
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#odersky-programming-in-scala-1ed #scala
Question
How does scala decide on precedence when methods are used in operator notation, like 2 + 2 * 7 ? What is Scala's default rule here?
Answer
?
Tags
#odersky-programming-in-scala-1ed #scala
Question
How does scala decide on precedence when methods are used in operator notation, like 2 + 2 * 7 ? What is Scala's default rule here?
Answer
Scala decides precedence based on the first character of the methods used in operator notation (this rule has exceptions). If the method name starts with a *, for example, it will have a higher precedence than a method that starts with a +.
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Basic Types and Operations he expression above to be 28, you could
write the expression like this:
(2 + 2) * 7
Given that Scala doesn't have operators, per se, just a way to use
methods in operator notation, you may be wondering how operator
precedence works. <span>Scala decides precedence based on the first
character of the methods used in operator notation (there's one
exception to this rule, which will be discussed below). If the method name
starts with a *, for example, it will have a higher precedence than
a method that starts with a +. Thus 2 + 2 * 7 will be evaluated
as 2 + (2 * 7), and a +++ b *** c (in which a, b, and c
are variables, and +++ and *** are methods) will be
evaluated a +++ (b *** c), because the *** method has a higher
precedence than the +++ method.
Table 5.3 here shows the precedence given to the first character of a method in decreasing order of precedence, with
characters on the same line having the same precedence. The high
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