In simple exponential smoothing satisfying the formula: \(\hat{x}_{n+1}\) = αxn + (1 − α)\(\hat{x}_n\)
if α =1, then \(\hat{x}_{n+1}\) = xn, so the 1-step ahead forecast is just the [...]value.
Answer
current
If you want to change selection, open original toplevel document below and click on "Move attachment"
Parent (intermediate) annotation
Open it In simple exponential smoothing satisfying the formula:
\hat{x}_{n+1} = αx n + (1 − α)\hat{x}_n
if α =1, then \hat{x}_{n+1} = x n , so the 1-step ahead forecast is just the current value.
Original toplevel document (pdf)
cannot see any pdfs
Summary
status
not learned
measured difficulty
37% [default]
last interval [days]
repetition number in this series
0
memorised on
scheduled repetition
scheduled repetition interval
last repetition or drill
Details
No repetitions
Discussion
Do you want to join discussion? Click here to log in or create user.