Tags
#m249 #mathematics #open-university #statistics #time-series
Question
In simple exponential smoothing satisfying the formula:
\(\hat{x}_{n+1}\) = αxn + (1 − α)\(\hat{x}_n\),
if α = 0, then \(\hat{x}_{n+1}\) = [...]
Answer
\(\hat{x}_{n+1}\) = \(\hat{x}_n\) = ··· = \(\hat{x}_1\) = x1, the initial value.
Tags
#m249 #mathematics #open-university #statistics #time-series
Question
In simple exponential smoothing satisfying the formula:
\(\hat{x}_{n+1}\) = αxn + (1 − α)\(\hat{x}_n\),
if α = 0, then \(\hat{x}_{n+1}\) = [...]
Tags
#m249 #mathematics #open-university #statistics #time-series
Question
In simple exponential smoothing satisfying the formula:
\(\hat{x}_{n+1}\) = αxn + (1 − α)\(\hat{x}_n\),
if α = 0, then \(\hat{x}_{n+1}\) = [...]
Answer
\(\hat{x}_{n+1}\) = \(\hat{x}_n\) = ··· = \(\hat{x}_1\) = x1, the initial value.
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