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Tags

#m249 #mathematics #open-university #statistics #time-series

Question

In simple exponential smoothing satisfying the formula:

\(\hat{x}_{n+1}\) = αx_{n} + (1 − α)\(\hat{x}_n\), the lower the value of α, the [smoother or rougher?] the forecasts will be because they are not aﬀected much by recent values.

\(\hat{x}_{n+1}\) = αx

Answer

smoother

Tags

#m249 #mathematics #open-university #statistics #time-series

Question

In simple exponential smoothing satisfying the formula:

\(\hat{x}_{n+1}\) = αx_{n} + (1 − α)\(\hat{x}_n\), the lower the value of α, the [smoother or rougher?] the forecasts will be because they are not aﬀected much by recent values.

\(\hat{x}_{n+1}\) = αx

Answer

?

Tags

#m249 #mathematics #open-university #statistics #time-series

Question

In simple exponential smoothing satisfying the formula:

\(\hat{x}_{n+1}\) = αx_{n} + (1 − α)\(\hat{x}_n\), the lower the value of α, the [smoother or rougher?] the forecasts will be because they are not aﬀected much by recent values.

\(\hat{x}_{n+1}\) = αx

Answer

smoother

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In simple exponential smoothing satisfying the formula: \hat{x}_{n+1} = αx n + (1 − α)\hat{x}_n, the lower the value of α, the smoother the forecasts will be because they are not aﬀected much by recent values.

#### Original toplevel document (pdf)

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In simple exponential smoothing satisfying the formula: \hat{x}_{n+1} = αx n + (1 − α)\hat{x}_n, the lower the value of α, the smoother the forecasts will be because they are not aﬀected much by recent values.

status | not learned | measured difficulty | 37% [default] | last interval [days] | |||
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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

scheduled repetition interval | last repetition or drill |

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