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#reading-9-probability-concepts

The number of ways to assign every member of a group of size *n* to *n* slots is *n*! = *n* (*n* − 1) (*n* − 2)(*n* − 3) … 1. (By convention, 0! = 1.)

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**Summary **

rst step in a process can be done in 10 ways, the second step, given the first, can be done in 5 ways, and the third step, given the first two, can be done in 7 ways, then the steps can be carried out in (10)(5)(7) = 350 ways. <span>The number of ways to assign every member of a group of size n to n slots is n! = n (n − 1) (n − 2)(n − 3) … 1. (By convention, 0! = 1.) The number of ways that n objects can be labeled with k different labels, with n 1 of the first type, n 2 of the second type, and so on, with n 1 + n 2 + … + n k =

rst step in a process can be done in 10 ways, the second step, given the first, can be done in 5 ways, and the third step, given the first two, can be done in 7 ways, then the steps can be carried out in (10)(5)(7) = 350 ways. <span>The number of ways to assign every member of a group of size n to n slots is n! = n (n − 1) (n − 2)(n − 3) … 1. (By convention, 0! = 1.) The number of ways that n objects can be labeled with k different labels, with n 1 of the first type, n 2 of the second type, and so on, with n 1 + n 2 + … + n k =

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