#has-images
Calculating the value of a parsec [ edit ]
[imagelink] In the diagram above (not to scale), S represents the Sun, and E the Earth at one point in its orbit. Thus the distance ES is one astronomical unit (au). The angle SDE is one arcsecond ( 1 / 3600 of a degree) so by definition D is a point in space at a distance of one parsec from the Sun. Through trigonometry, the distance SD is calculated as follows:
\({\displaystyle \mathrm {SD} ={\frac {\mathrm {ES} }{\tan 1''}}}\) \({\displaystyle \mathrm {SD} \approx {\frac {\mathrm {ES} }{1''}}={\frac {1\,{\mbox{au}}}{{\frac {1}{60\times 60}}\times {\frac {\pi }{180}}}}={\frac {648\,000}{\pi }}\,{\mbox{au}}\approx 206\,264.81{\mbox{ au}}.}\)
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Parsec - Wikipediassed his concern for the need of a name for that unit of distance. He proposed the name astron, but mentioned that Carl Charlier had suggested siriometer and Herbert Hall Turner had proposed parsec. [3] It was Turner's proposal that stuck.
<span>Calculating the value of a parsec[edit]
[imagelink]
In the diagram above (not to scale), S represents the Sun, and E the Earth at one point in its orbit. Thus the distance ES is one astronomical unit (au). The angle SDE is one arcsecond (1/3600 of a degree) so by definition D is a point in space at a distance of one parsec from the Sun. Through trigonometry, the distance SD is calculated as follows:
S
D
=
E
S
tan
1
″
{\displaystyle \mathrm {SD} ={\frac {\mathrm {ES} }{\tan 1''}}}
S
D
≈
E
S
1
″
=
1
au
1
60
×
60
×
π
180
=
648
000
π
au
≈
206
264.81
au
.
{\displaystyle \mathrm {SD} \approx {\frac {\mathrm {ES} }{1''}}={\frac {1\,{\mbox{au}}}{{\frac {1}{60\times 60}}\times {\frac {\pi }{180}}}}={\frac {648\,000}{\pi }}\,{\mbox{au}}\approx 206\,264.81{\mbox{ au}}.}
Because the astronomical unit is defined to be 7011149597870700000♠149597870700 m, [8] the following can be calculated:
Therefore, 1 parsec ≈ 7005206264806247096♠206264.8062470 Summary
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