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Calculating the value of a parsec [ edit ]

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In the diagram above (not to scale), S represents the Sun, and E the Earth at one point in its orbit. Thus the distance ES is one astronomical unit (au). The angle SDE is one arcsecond ( 1 / 3600 of a degree) so by definition D is a point in space at a distance of one parsec from the Sun. Through trigonometry, the distance SD is calculated as follows:

\({\displaystyle \mathrm {SD} ={\frac {\mathrm {ES} }{\tan 1''}}}\) \({\displaystyle \mathrm {SD} \approx {\frac {\mathrm {ES} }{1''}}={\frac {1\,{\mbox{au}}}{{\frac {1}{60\times 60}}\times {\frac {\pi }{180}}}}={\frac {648\,000}{\pi }}\,{\mbox{au}}\approx 206\,264.81{\mbox{ au}}.}\)
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Parsec - Wikipedia
ssed his concern for the need of a name for that unit of distance. He proposed the name astron, but mentioned that Carl Charlier had suggested siriometer and Herbert Hall Turner had proposed parsec. [3] It was Turner's proposal that stuck. <span>Calculating the value of a parsec[edit] [imagelink] In the diagram above (not to scale), S represents the Sun, and E the Earth at one point in its orbit. Thus the distance ES is one astronomical unit (au). The angle SDE is one arcsecond (1/3600 of a degree) so by definition D is a point in space at a distance of one parsec from the Sun. Through trigonometry, the distance SD is calculated as follows: S D = E S tan ⁡ 1 ″ {\displaystyle \mathrm {SD} ={\frac {\mathrm {ES} }{\tan 1''}}} S D ≈ E S 1 ″ = 1 au 1 60 × 60 × π 180 = 648 000 π au ≈ 206 264.81 au . {\displaystyle \mathrm {SD} \approx {\frac {\mathrm {ES} }{1''}}={\frac {1\,{\mbox{au}}}{{\frac {1}{60\times 60}}\times {\frac {\pi }{180}}}}={\frac {648\,000}{\pi }}\,{\mbox{au}}\approx 206\,264.81{\mbox{ au}}.} Because the astronomical unit is defined to be 7011149597870700000♠149597870700 m, [8] the following can be calculated: Therefore, 1 parsec ≈ 7005206264806247096♠206264.8062470


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