Show that any odd number can be written as the difference of two squares.
Let the odd number be \( n = 2b + 1 \), where \(b\) is a non-negative integer. Then we have
\[ n = 2b+1 = [ (b+1) + b ] [ (b+1) - b ] = (b+1)^2 - b^2. \ _\square\]
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