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Question

A sausage making machine occasionally produces misshapen sausages. The odds of the machine producing 0, 1, 2, 3, 4, or 5 sausages are .09, .07, .1, .04, .12 and .02 respectively. Find the variance and standard deviation.

Answer

1 Find and square the mean (here .81). Set this number aside.
2 Make a probability distribution chart :

Number of misshapper sausages X	0	1	2	3	4	5
Proability P(X)	.09	.07	.1	.04	.12	.02

3 Square the top number, X, and multiply it by the bottom number ,P(X).
4: Add all of the numbers together.
5\(\sqrt{Step\ 4-Step\ 1}\)= SD

Question

Answer

Question

Answer

1 Find and square the mean (here .81). Set this number aside.
2 Make a probability distribution chart :

Number of misshapper sausages X	0	1	2	3	4	5
Proability P(X)	.09	.07	.1	.04	.12	.02

3 Square the top number, X, and multiply it by the bottom number ,P(X).
4: Add all of the numbers together.
5\(\sqrt{Step\ 4-Step\ 1}\)= SD

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pdf

owner: naxplast06 - (no access) - Deviant S. - The Practically Cheating Statistics Handbook (2010, CreateSpace Independent Publishing Platform).pdf, p75

Summary

status	not learned	measured difficulty	37% [default]	last interval [days]
repetition number in this series	0	memorised on		scheduled repetition
scheduled repetition interval		last repetition or drill

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