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Question

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Question

In linux, write simple bash script that prints out all the command line arguments of the script no matter how many or few (e.g. if you run script test.sh as "./tests.sh one two three", it will print out "one\n two\n three")

Answer

#!/bin/bash
while [ "$1" != "" ]; do
    echo $1
    shift
done

^^ note the use of shift
^^ also note the "$1" in the conditional clause of while loop (line 2) wrapped in "", as this is needed for string comparison!!!

Question

Answer

Question

Answer

#!/bin/bash
while [ "$1" != "" ]; do
    echo $1
    shift
done

^^ note the use of shift
^^ also note the "$1" in the conditional clause of while loop (line 2) wrapped in "", as this is needed for string comparison!!!

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7. Shell Scripting
d argument is: birds Now we need to loop through each argument and decide what to do with it. A script like for i in $1 $2 $3 $4 ; do <statments> done doesn't give us much flexibilty. The <span>shift keyword is meant to make things easier. It shifts up all the arguments by one place so that $1 gets the value of $2 , $2 gets the value of $3 , and so on. ( != tests that the "$1" is no

Summary

status	not learned	measured difficulty	37% [default]	last interval [days]
repetition number in this series	0	memorised on		scheduled repetition
scheduled repetition interval		last repetition or drill

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