BuboFlash - helps with learning

Do you want BuboFlash to help you learning these things? Or do you want to add or correct something? Click here to log in or create user.

Presentation
Question

Answer

Question

In algorithms, for BinarySearchTree class' insert method (def insert(self, data): ), you 1) create the Node object from the data 2) check to see if root is empty (if so make the new Node root), 3) if root is not empty, create current pointer to root, and parent pointer (to None initially) 4) [...] 5) in loop, check value of current (compared to new Node data) to see if current is to shift to right or left subtree and if current is None, you found right place to insert (so short circuit loop)

class Node:        
    def __init__(self, data):            
        self.data = data
        self.left_child = None
        self.right_child = None


class Tree:        
    def __init__(self):            
        self.root_node = None


    def insert(self, data):
        # 1. create the Node object with the data
        node = Node(data)
        # 2. if root is None, make this new node the root
        if self.root_node == None:            
            self.root_node = node        
        else:
            # 3. if root exists, then create a current pointer initialized to root, and a parent pointer (None initially)
            current = self.root_node        
            parent = None 
            # 4. ???????????????????????????????????????????????????????????
            ????????????????????????????????????????????????????????????????            
                ????????????????????????????????????????????????????????????
                # 5. in loop compare the new node data to current node data and either go left side
                #    or right side of tree (and if you hit current of None, use the parent pointer to insert new node and
                     short circuit loop, other wise the loop will continue down the tree
                if node.data <= current.data:
                    current = current.left_child
                    if current is None:
                        parent.left_child = node
                        return
                else:
                    current = current.right_child
                    if current is None:
                        parent.right_child = node
                        return

Answer

go into "while True:" loop and in loop make parent the current

            # 4. go into "while True:" loop and in loop make parent the current  
            while True:            
                parent = current

Question

class Node:        
    def __init__(self, data):            
        self.data = data
        self.left_child = None
        self.right_child = None


class Tree:        
    def __init__(self):            
        self.root_node = None


    def insert(self, data):
        # 1. create the Node object with the data
        node = Node(data)
        # 2. if root is None, make this new node the root
        if self.root_node == None:            
            self.root_node = node        
        else:
            # 3. if root exists, then create a current pointer initialized to root, and a parent pointer (None initially)
            current = self.root_node        
            parent = None 
            # 4. ???????????????????????????????????????????????????????????
            ????????????????????????????????????????????????????????????????            
                ????????????????????????????????????????????????????????????
                # 5. in loop compare the new node data to current node data and either go left side
                #    or right side of tree (and if you hit current of None, use the parent pointer to insert new node and
                     short circuit loop, other wise the loop will continue down the tree
                if node.data <= current.data:
                    current = current.left_child
                    if current is None:
                        parent.left_child = node
                        return
                else:
                    current = current.right_child
                    if current is None:
                        parent.right_child = node
                        return

Answer

Question

class Node:        
    def __init__(self, data):            
        self.data = data
        self.left_child = None
        self.right_child = None


class Tree:        
    def __init__(self):            
        self.root_node = None


    def insert(self, data):
        # 1. create the Node object with the data
        node = Node(data)
        # 2. if root is None, make this new node the root
        if self.root_node == None:            
            self.root_node = node        
        else:
            # 3. if root exists, then create a current pointer initialized to root, and a parent pointer (None initially)
            current = self.root_node        
            parent = None 
            # 4. ???????????????????????????????????????????????????????????
            ????????????????????????????????????????????????????????????????            
                ????????????????????????????????????????????????????????????
                # 5. in loop compare the new node data to current node data and either go left side
                #    or right side of tree (and if you hit current of None, use the parent pointer to insert new node and
                     short circuit loop, other wise the loop will continue down the tree
                if node.data <= current.data:
                    current = current.left_child
                    if current is None:
                        parent.left_child = node
                        return
                else:
                    current = current.right_child
                    if current is None:
                        parent.right_child = node
                        return

Answer

go into "while True:" loop and in loop make parent the current

            # 4. go into "while True:" loop and in loop make parent the current  
            while True:            
                parent = current

If you want to change selection, open document below and click on "Move attachment"

pdf

owner: kkhosravi - (no access) - PYTHON_DATA_STRUCTURES_AND_ALGORITHMS.pdf, p155

Summary

status	not learned	measured difficulty	37% [default]	last interval [days]
repetition number in this series	0	memorised on		scheduled repetition
scheduled repetition interval		last repetition or drill

Details

No repetitions

Discussion

Do you want to join discussion? Click here to log in or create user.