kinetics On integration Eq. (2.1) gives: = µ xxe t t 0 (2.2) where x 0 is the original biomass concentration, x t is the biomass concentration after the time interval, t hours, e is the base of the natural logarithm. On taking natural logarithms, Eq. (2.2) becomes: µ =+ xxtln
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[default - edit me]
Answer
kinetics On integration Eq. (2.1) gives: = µ xxe t t 0 (2.2) where x 0 is the original biomass concentration, x t is the biomass concentration after the time interval, t hours, e is the base of the natural logarithm. On taking natural logarithms, Eq. (2.2) becomes: µ =+ xxtln
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owner: stuckonrepeat21 - (no access) - Principles of Fermentation Technology (Peter F Stanbury, Allan Whitaker etc.) (z-lib.org).pdf, p28
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