复数向量所在区间与其幅角的关系
复数向量所在区间与其幅角的关系：\(\theta=\tan^{-1}\left(\frac{y}{x}\right)= \begin{cases}\tan^{-1}\left(\frac{y}{x}\right) & \text { if } x>0 \\\pi-\tan^{-1}\left(\frac{y}{-x}\right) & \text { if } x<0 \text { and } y \geq 0 \\-\left(\pi-\tan^{-1}\left(\frac{y}{x}\right)\right) & \text { if } x<0 \text { and } y<0 \\ +\frac{\pi}{2} & \text { if } x=0 \text { and } y>0 \\ -\frac{\pi}{2} & \text { if } x=0 \text { and } y<0 \\ \text { undefined } & \text { if } x=0 \text { and } y=0\end{cases}\)
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