Question
对一个满足分段连续的函数\(f(t)\)做傅里叶变换,可以将其从时域(\(t\))转换到频域(\(\omega\)),它的定义为:[...]
Answer
\(\displaystyle {\hat{f}(\omega)=\mathcal {F}}[f(t)]=\int _{-\infty}^{+\infty }f(t)e^{-i\omega t}\,\mathrm {d} t\)
Question
对一个满足分段连续的函数\(f(t)\)做傅里叶变换,可以将其从时域(\(t\))转换到频域(\(\omega\)),它的定义为:[...]
Question
对一个满足分段连续的函数\(f(t)\)做傅里叶变换,可以将其从时域(\(t\))转换到频域(\(\omega\)),它的定义为:[...]
Answer
\(\displaystyle {\hat{f}(\omega)=\mathcal {F}}[f(t)]=\int _{-\infty}^{+\infty }f(t)e^{-i\omega t}\,\mathrm {d} t\)
If you want to change selection, open document below and click on "Move attachment"
Definition of Fourier Transform 对一个满足分段连续的函数\(f(t)\)做傅里叶变换,可以将其从时域(\(t\))转换到频域(\(\omega\)),它的定义为:\(\displaystyle {\hat{f}(\omega)=\mathcal {F}}[f(t)]=\int _{-\infty}^{+\infty }f(t)e^{-i\omega t}\,\mathrm {d} t\) Summary
status | not learned | | measured difficulty | 37% [default] | | last interval [days] | |
---|
repetition number in this series | 0 | | memorised on | | | scheduled repetition | |
---|
scheduled repetition interval | | | last repetition or drill | | | | |
---|
Details
No repetitions