Answer
For any two events \(A\) and \(B\) with \(P(B) > 0\), \(P(A|B) = P(B|A) \frac{P(A)}{P(B)}\)
Answer
For any two events \(A\) and \(B\) with \(P(B) > 0\), \(P(A|B) = P(B|A) \frac{P(A)}{P(B)}\)
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Bayes’ Theorem Bayes’ Theorem: For any two events \(A\) and \(B\) with \(P(B) > 0\), \(P(A|B) = P(B|A) \frac{P(A)}{P(B)}\) Summary
status | not learned | | measured difficulty | 37% [default] | | last interval [days] | |
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repetition number in this series | 0 | | memorised on | | | scheduled repetition | |
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scheduled repetition interval | | | last repetition or drill | | | | |
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Details
No repetitions