BuboFlash - helps with learning

Edited, memorised or added to reading queue

Do you want BuboFlash to help you learning these things? Click here to log in or create user.

Flashcard 7621052599564

Question

MOS管的氧化物层可以看做绝缘电解质，金属、半导体可以看做两个电极，其金属-氧化物-半导体结构构成了一个电容，被称为MOS电容，这个电容对MOS管特性有重要影响。其电容公式为：[...]

Answer

\(C_{ox}=\frac{\varepsilon_{0}\varepsilon_{r}A}{d_{ox}}\)

其中\(A(cm^{2})\)为MOS电容的面积，\(d_{ox}(cm)\)为氧化物层的厚度，\(\varepsilon_{0}\varepsilon_{r}(F/cm)\)为氧化物的电容率

status	not learned	measured difficulty	37% [default]	last interval [days]
repetition number in this series	0	memorised on		scheduled repetition
scheduled repetition interval		last repetition or drill

Flashcard 7621054958860

Question

随着MOS电容输入电压\(V_{GS}\)的增加，MOS电容的工作模式会逐渐变化。MOS电容的工作模式有：[...]

Answer

- 积累模式(Accumulation, small \(V_{GS}<0\))
- 耗尽模式(Depletion, \(0<V_{GS}<V_{th}\))
- 反向模式(Inversion, \(V_{GS}>V_{th}\))

status	not learned	measured difficulty	37% [default]	last interval [days]
repetition number in this series	0	memorised on		scheduled repetition
scheduled repetition interval		last repetition or drill

\(\begin{array}{rl}V_{th}&=&V_{fb}+V_{inv}+V_{dep}\\&=&\displaystyle \left(\Phi_{m}-\Phi_{s}- \frac{Q}{C'_{ox}}\right)+2 \frac{kT}{q}\ln\left(\frac{N_{A}}{n_{i}}\right)+2 \frac{\sqrt{qN_{A}\varepsilon V_{bi}}}{C'_{ox}}\end{array}\)

其中\(\Phi_{m}\)为栅极材料的功函数（work function），\(\Phi_{s}\)为半导体材料功函数，\(Q\)为氧化物层电荷量，\(C'_{ox}\)为MOS电容的电容量，\(q\)为电子电荷量（\(1.6\times10^{-19}C\)），\(N_{A}\)为衬底半导体材料的掺杂载流子浓度，\(\varepsilon\)为衬底半导体材料的电容率（\(\varepsilon=\varepsilon_{r}\varepsilon_{0}\)）

status	not learned	measured difficulty	37% [default]	last interval [days]
repetition number in this series	0	memorised on		scheduled repetition
scheduled repetition interval		last repetition or drill

Edited, memorised or added to reading queue

on 21-Mar-2024 (Thu)

Flashcard 7621048929548

Flashcard 7621052599564

Flashcard 7621054958860

Flashcard 7621057842444