Proposition: Every element in a vector space has a unique additive inverse. Proof: [...]
Answer
Suppose V is a vector space. Let v ∈ V. Suppose that w and w' are additive inverses of v. Then w' = w' + 0 = w' +(v + w) = (w'+v)+w = 0 + w = w. Thus w = w', as desired.
Question
Proposition: Every element in a vector space has a unique additive inverse. Proof: [...]
Answer
?
Question
Proposition: Every element in a vector space has a unique additive inverse. Proof: [...]
Answer
Suppose V is a vector space. Let v ∈ V. Suppose that w and w' are additive inverses of v. Then w' = w' + 0 = w' +(v + w) = (w'+v)+w = 0 + w = w. Thus w = w', as desired.
If you want to change selection, open original toplevel document below and click on "Move attachment"
Parent (intermediate) annotation
Open it Proposition: Every element in a vector space has a unique additive inverse. Proof: Suppose V is a vector space. Let v ∈ V. Suppose that w and w' are additive inverses of v. Then w' = w' + 0 = w' +(v + w) = (w'+v)+w = 0 + w = w. Thus w = w', as desired.
Original toplevel document (pdf)
owner: eshi - (no access) - Sheldon_Axler_Linear_Algebra_Done_Right.pdf, p25
Summary
status
not learned
measured difficulty
37% [default]
last interval [days]
repetition number in this series
0
memorised on
scheduled repetition
scheduled repetition interval
last repetition or drill
Details
No repetitions
Discussion
Do you want to join discussion? Click here to log in or create user.