Question
Proposition: Every element in a vector space has a unique additive inverse. Proof: [...]
Suppose V is a vector space. Let v ∈ V. Suppose that w and w' are additive inverses of v. Then w' = w' + 0 = w' +(v + w) = (w'+v)+w = 0 + w = w. Thus w = w', as desired.

Question
Proposition: Every element in a vector space has a unique additive inverse. Proof: [...]
?

Question
Proposition: Every element in a vector space has a unique additive inverse. Proof: [...]
Suppose V is a vector space. Let v ∈ V. Suppose that w and w' are additive inverses of v. Then w' = w' + 0 = w' +(v + w) = (w'+v)+w = 0 + w = w. Thus w = w', as desired.
If you want to change selection, open original toplevel document below and click on "Move attachment"

#### Parent (intermediate) annotation

Open it
Proposition: Every element in a vector space has a unique additive inverse. Proof: Suppose V is a vector space. Let v ∈ V. Suppose that w and w' are additive inverses of v. Then w' = w' + 0 = w' +(v + w) = (w'+v)+w = 0 + w = w. Thus w = w', as desired.

#### Original toplevel document (pdf)

owner: eshi - (no access) - Sheldon_Axler_Linear_Algebra_Done_Right.pdf, p25

#### Summary

status measured difficulty not learned 37% [default] 0

No repetitions