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Tags
#scala
Question
// Inline add and addR
def sum(ns: Int*): Int = ns.foldLeft(0)((n, m) => n + m) // inlined add

scala> sum(33, 42, 99)
res2: Int = 174 // alright

def sumR(ns: Int*): Int = ns.foldLeft(0)((n, m) => return n + m) // inlined addR

scala> sumR(33, 42, 99)
res3: ???
What will this expression return and why?
Answer
33 // um.

A return expression, when evaluated, abandons the current computation and returns to the caller of the method in which return appears.

Tags
#scala
Question
// Inline add and addR
def sum(ns: Int*): Int = ns.foldLeft(0)((n, m) => n + m) // inlined add

scala> sum(33, 42, 99)
res2: Int = 174 // alright

def sumR(ns: Int*): Int = ns.foldLeft(0)((n, m) => return n + m) // inlined addR

scala> sumR(33, 42, 99)
res3: ???
What will this expression return and why?
Answer
?

Tags
#scala
Question
// Inline add and addR
def sum(ns: Int*): Int = ns.foldLeft(0)((n, m) => n + m) // inlined add

scala> sum(33, 42, 99)
res2: Int = 174 // alright

def sumR(ns: Int*): Int = ns.foldLeft(0)((n, m) => return n + m) // inlined addR

scala> sumR(33, 42, 99)
res3: ???
What will this expression return and why?
Answer
33 // um.

A return expression, when evaluated, abandons the current computation and returns to the caller of the method in which return appears.
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Parent (intermediate) annotation

Open it
Int*): Int = ns.foldLeft(0)((n, m) => n + m) // inlined add scala> sum(33, 42, 99) res2: Int = 174 // alright def sumR(ns: Int*): Int = ns.foldLeft(0)((n, m) => return n + m) // inlined addR scala> sumR(33, 42, 99) res3: Int = <span>33 // um. <span><body><html>

Original toplevel document

tpolecat
(addR) scala> sumR(33, 42, 99) res1: Int = 174 So far so good. There is no apparent difference between sum and sumR which may lead you to think that return is simply an optional keyword. But let's refactor a bit by inlining add and addR. <span>// Inline add and addR def sum(ns: Int*): Int = ns.foldLeft(0)((n, m) => n + m) // inlined add scala> sum(33, 42, 99) res2: Int = 174 // alright def sumR(ns: Int*): Int = ns.foldLeft(0)((n, m) => return n + m) // inlined addR scala> sumR(33, 42, 99) res3: Int = 33 // um. What the what? So, the short version is: A return expression, when evaluated, abandons the current computation and returns to the caller of the method in which return appears. So in

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