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#ytt #ytt-2 #ytt-2-tilinpäätösanalyysi_omistajan_näkökulmasta #ytt-2.2-tilinpäätösanalyysi_osana_yrityksen_arvon_määritystä

tilinpäätösnormistot ja niiden tulkinnat vääristävät tilinpäätöksiä. Haasteena näissä epäkohdissa on se, ettei ulkopuolisella arvioitsijalla ole useinkaan riittäviä tietoja näiden epäkohtien eliminoimiseen

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#has-images

Question

What is the formula for the variance and the Standard Deviation of a given value in a sample?

Answer

Which means : (sum of squares - (square of the sum/number of items))/(number of items - 1)

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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

scheduled repetition interval | last repetition or drill |

Question

How to draw a frequency distribution table?

Answer

1. Subtract the minimum data value from the maximum data value and divide by the number of classes (NCLASS) you

chose (between 5 and 20, so you have a few items in each class).

2. Step 1 rounded up gives you the class width. Add class width NCLASS times to the minimum value so you have the lower limits of your classes. The upper limits = lower limits + class width -1

3. Count how many values there is in each class

chose (between 5 and 20, so you have a few items in each class).

2. Step 1 rounded up gives you the class width. Add class width NCLASS times to the minimum value so you have the lower limits of your classes. The upper limits = lower limits + class width -1

3. Count how many values there is in each class

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Question

A left-skewed distribution has a mean of 4.99 and a standard deviation of 3.13. Use Chebyshev’s Theorem to calculate the proportion of observation you would expect to find within two standard deviations (in other words, between -2 and +2 standard deviations) from the mean

Answer

1-1/(number of SD)^2 = 75%

The mean has no effect on Chebyshev's ! Results can be inaccurate in some cases

The mean has no effect on Chebyshev's ! Results can be inaccurate in some cases

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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

scheduled repetition interval | last repetition or drill |

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#has-images

Question

Find the probability of selecting a person at random : At a school board meeting there are 9 parents and 5 teachers. 2 teachers and 5 parents are female. If a person at the school board meeting is selected at random, find the probability that the person is a parent or a female.

Answer

Then add up the probabilities: (9+7)/14 =16/14. And subtract the intersection of probability [FEMALE AND TEACHER] not to count it twice

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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

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Question

Figure out the odds of getting certain cards drawn from a deck : a certain number card (i.e. a 7) or one from a certain suit (i.e. a club).

Answer

we’ve been asked the probability of a club or a 7 so we’re going to mark all the clubs and all the sevens:

hearts: 2, 3, 4, 5, 6, 7 , 8, 9, 10, J, Q, K, A

clubs: 2, 3, 4, 5, 6, 7, 8, 9, 10, J , Q , K , A

spades: 2, 3, 4, 5, 6, 7 , 8, 9, 10, J, Q, K, A

diamonds: 2, 3, 4, 5, 6, 7 , 8, 9, 10, J, Q, K, A

This totals 16 cards.

hearts: 2, 3, 4, 5, 6, 7 , 8, 9, 10, J, Q, K, A

clubs: 2, 3, 4, 5, 6, 7, 8, 9, 10, J , Q , K , A

spades: 2, 3, 4, 5, 6, 7 , 8, 9, 10, J, Q, K, A

diamonds: 2, 3, 4, 5, 6, 7 , 8, 9, 10, J, Q, K, A

This totals 16 cards.

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#test

A similar situation happens with two rotating inertias, each of which is individually modeled using the angle of rotation and the angular velocity. Two states will disappear when the inertias are joined by a rigid shaft. This difficulty can be avoided by replacing differential equations by differential algebraic equations, which have the form F(z, ˙z) = 0, where z ∈ R n . A simple special case is ˙x = f (x, y), g(x, y) = 0, (2.4) where z = (x, y) and F = ( ˙x − f (x, y), g(x, y)). The key property is that the derivative ˙z is not given explicitl

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#test

Modelica

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#test

State models or ordinary differential equations are not suitable for component- based modeling of this form because states may disappear when components are connected.

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#test

Question

[...] or ordinary differential equations are not suitable for component- based modeling of this form because states may disappear when components are connected.

Answer

State models

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State models or ordinary differential equations are not suitable for component- based modeling of this form because states may disappear when components are connected.

Tags

#test

Question

State models or [...] are not suitable for component- based modeling of this form because states may disappear when components are connected.

Answer

ordinary differential equations

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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

scheduled repetition interval | last repetition or drill |

State models or ordinary differential equations are not suitable for component- based modeling of this form because states may disappear when components are connected.

Question

If P(A) = .20, P(B) =. 35 , and (A U B) = . 51, then are A and B mutually exclusive?

Answer

No because .20 + .35 = .55 is different from .55

status | not learned | measured difficulty | 37% [default] | last interval [days] | |||
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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

scheduled repetition interval | last repetition or drill |

Question

How to tell the difference between a dependent and independent event?

Answer

1. Is it possible for the events to occur in any order?

2. Does one event in any wa y affect the outcome (or the odds) of the other event?

2. Does one event in any wa y affect the outcome (or the odds) of the other event?

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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

scheduled repetition interval | last repetition or drill |

Question

Determining if a question concerns a binomial experiment involves asking four questions about the problem, which are :

Answer

Step 1: Are there a fixed number of trials?

Step 2: Are there only 2 possible outcomes?

Step 3: Are the outcomes independent of each other? In other words, does the outcome of one trial (or one toss, or one question) affect another trial?

Step 4:Does the probability of success remain the same for each trial?

Step 2: Are there only 2 possible outcomes?

Step 3: Are the outcomes independent of each other? In other words, does the outcome of one trial (or one toss, or one question) affect another trial?

Step 4:Does the probability of success remain the same for each trial?

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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

scheduled repetition interval | last repetition or drill |