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#9-dic-2016 #el-financiero #enrique-quintana #noticias

Question

Answer

Steve Bannon

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Breibart News Network, el medio ultranacionalista fundado por Steve Bannon, quien ha sido nombrado por Trump como su Consejero Principal y Jefe de Estrategia.

n a los senadores del PRD el recordatorio materno que le mandaron a Donald Trump cuando le pegaron a una piñata con su figura en su reunión navideña. Más gusto les habrá dado que el video de ese evento haya llegado a las páginas de <span>Breibart News Network, el medio ultranacionalista fundado por Steve Bannon, quien ha sido nombrado por Trump como su Consejero Principal y Jefe de Estrategia. A media tarde, se podían leer en dicho sitio más de mil comentarios a este video, el segundo más comentado del sitio, sólo por debajo de uno de Leonardo Di Caprio.

Tags

#cfa #cfa-level-1 #economics #microeconomics #reading-13-demand-and-supply-analysis-introduction #study-session-4

Question

For every unit up to the equilibrium unit traded, buyers would have been willing to pay [...].

Answer

more than they actually had to pay

status | not learned | measured difficulty | 37% [default] | last interval [days] | |||
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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

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For every unit up to the equilibrium unit traded, buyers would have been willing to pay more than they actually had to pay. Additionally, for every one of those units, sellers would have been willing to sell it for less than they actually received. The total value to buyers was greater than the total variab

In the previous sections, we have seen that consumers and producers both receive “a bargain” when they are allowed to engage in a mutually beneficial, voluntary exchange with one another. For every unit up to the equilibrium unit traded, buyers would have been willing to pay more than they actually had to pay. Additionally, for every one of those units, sellers would have been willing to sell it for less than they actually received. The total value to buyers was greater than the total variable cost to sellers. The difference between those two values is called total surplus , and it is made up of the sum of consumer surplus and producer surplus. Note that the way the total surplus is divided between consumers and producers depends on the steepness of the d

Tags

#cfa #cfa-level-1 #economics #microeconomics #reading-14-demand-and-supply-analysis-consumer-demand #section-3-utility-theory #study-session-4

Question

we could construct any number of indifference curves. The result is an entire family of indifference curves, called an [...] ,

Answer

status | not learned | measured difficulty | 37% [default] | last interval [days] | |||
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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

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body>we could construct any number of indifference curves in the same manner we made the first indifference curve, simply by starting at a different initial bundle. The result is an entire family of indifference curves, called an indifference curve map ,<body><html>

goods. In that case, we could have gone through the same process of trial and error, and we would have ended up with another indifference curve, this one passing through the new point and lying above and to the right of the first one. Indeed, <span>we could construct any number of indifference curves in the same manner simply by starting at a different initial bundle. The result is an entire family of indifference curves, called an indifference curve map , and it represents our consumer’s entire utility function. The word map is appropriate because the entire set of indifference curves comprises a contour map of this consumer’s utility fu

#4 #acute #cardiac #chapter #diffusion #education #lung #output #physical #responses #rr #sv #tv #ventilation

Body systems Role Response to HI Respiratory Take up/uptake oxygen Lag Cardiovascular Transport/deliver oxygen/capacity Lag Muscular Use/metabolise energy Acute responses Time Length of adaptation Involve Example Acute Immediate Return after exercise respiratory, cardiovascular muscular Can't increase size of left ventricle supply more energy / ATP and oxygen to working muscles and to remove any waste products Chronic Long time (min 6 weeks) 2-3 wk to return to pre-exercise Can increase size of left ventricle and muscle wall to increase tidal volume Body needs during exercise

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#matlab #programming

Question

If you want to specify one of the minimum or maximum of a set of axis limits, but want MATLAB to autoscale the other, use [...] for the autoscaled limit

Answer

Inf or -Inf

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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

scheduled repetition interval | last repetition or drill |

If you want to specify one of the minimum or maximum of a set of axis limits, but want MATLAB to autoscale the other, use Inf or -Inf for the autoscaled limit

Question

There are typically 40 million bacterial cells in a [...] of soil and a million bacterial cells in a millilitre of fresh water.

Answer

gram

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There are typically 40 million bacterial cells in a gram of soil and a million bacterial cells in a millilitre of fresh water.

with plants and animals. Most bacteria have not been characterised, and only about half of the bacterial phyla have species that can be grown in the laboratory. [5] The study of bacteria is known as bacteriology, a branch of microbiology. <span>There are typically 40 million bacterial cells in a gram of soil and a million bacterial cells in a millilitre of fresh water. There are approximately 5×10 30 bacteria on Earth, [6] forming a biomass which exceeds that of all plants and animals. [7] Bacteria are vital in many stages of the nutrient cycle by

Question

There are typically 40 million bacterial cells in a gram of soil and [...] bacterial cells in a millilitre of fresh water.

Answer

a million

status | not learned | measured difficulty | 37% [default] | last interval [days] | |||
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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

scheduled repetition interval | last repetition or drill |

There are typically 40 million bacterial cells in a gram of soil and a million bacterial cells in a millilitre of fresh water.

with plants and animals. Most bacteria have not been characterised, and only about half of the bacterial phyla have species that can be grown in the laboratory. [5] The study of bacteria is known as bacteriology, a branch of microbiology. <span>There are typically 40 million bacterial cells in a gram of soil and a million bacterial cells in a millilitre of fresh water. There are approximately 5×10 30 bacteria on Earth, [6] forming a biomass which exceeds that of all plants and animals. [7] Bacteria are vital in many stages of the nutrient cycle by

Tags

#matlab #programming

Question

You can return to the default of automatic axis scaling with [...]

Answer

axis auto

status | not learned | measured difficulty | 37% [default] | last interval [days] | |||
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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

scheduled repetition interval | last repetition or drill |

You can return to the default of automatic axis scaling with axis auto

Tags

#matlab #programming

Question

You can [...] with axis auto

Answer

return to the default of automatic axis scaling

status | not learned | measured difficulty | 37% [default] | last interval [days] | |||
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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

scheduled repetition interval | last repetition or drill |

You can return to the default of automatic axis scaling with axis auto

Tags

#bayes #programming #r #statistics

Question

The ratio of the transition probabilities is [...] =

\(\frac {1} {P(\theta)/P(\theta+1)} \) (if P(\theta+1) > P(\theta))

\(\frac {P(\theta)/P(\theta+1)} {1}\) (if P(\theta+1) < P(\theta))

= \(\frac{P(\theta+1)} {P(\theta)}\)

\(\frac {1} {P(\theta)/P(\theta+1)} \) (if P(\theta+1) > P(\theta))

\(\frac {P(\theta)/P(\theta+1)} {1}\) (if P(\theta+1) < P(\theta))

= \(\frac{P(\theta+1)} {P(\theta)}\)

Answer

\(\frac{p(θ → θ +1)}{ p(θ +1 → θ)} = \frac{0.5 min ( P(θ +1)/P(θ),1 )}{ 0.5 min ( P(θ)/P(θ +1),1 )}\)

status | not learned | measured difficulty | 37% [default] | last interval [days] | |||
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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

scheduled repetition interval | last repetition or drill |

The ratio of the transition probabilities is \(\frac{p(θ → θ +1)}{ p(θ +1 → θ)} = \frac{0.5 min ( P(θ +1)/P(θ),1 )}{ 0.5 min ( P(θ)/P(θ +1),1 )}\) = \(\frac {1} {P(\theta)/P(\theta+1)} \) (if P(\theta+1) > P(\theta)) \(\frac {P(\theta)/P(\theta+1)} {1}\) (if P(\theta+1) < P(\theta)) = \(\frac{P(\t

Tags

#bayes #programming #r #statistics

Question

The ratio of the transition probabilities is \(\frac{p(θ → θ +1)}{ p(θ +1 → θ)} = \frac{0.5 min ( P(θ +1)/P(θ),1 )}{ 0.5 min ( P(θ)/P(θ +1),1 )}\) =

[...] (if P(\theta+1) > P(\theta))

\(\frac {P(\theta)/P(\theta+1)} {1}\) (if P(\theta+1) < P(\theta))

= \(\frac{P(\theta+1)} {P(\theta)}\)

[...] (if P(\theta+1) > P(\theta))

\(\frac {P(\theta)/P(\theta+1)} {1}\) (if P(\theta+1) < P(\theta))

= \(\frac{P(\theta+1)} {P(\theta)}\)

Answer

\(\frac {1} {P(\theta)/P(\theta+1)} \)

status | not learned | measured difficulty | 37% [default] | last interval [days] | |||
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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

scheduled repetition interval | last repetition or drill |

The ratio of the transition probabilities is \(\frac{p(θ → θ +1)}{ p(θ +1 → θ)} = \frac{0.5 min ( P(θ +1)/P(θ),1 )}{ 0.5 min ( P(θ)/P(θ +1),1 )}\) = \(\frac {1} {P(\theta)/P(\theta+1)} \) (if P(\theta+1) > P(\theta)) \(\frac {P(\theta)/P(\theta+1)} {1}\) (if P(\theta+1) < P(\theta)) = \(\frac{P(\theta+1)} {P(\theta)}\) </b

Tags

#bayes #programming #r #statistics

Question

The ratio of the transition probabilities is \(\frac{p(θ → θ +1)}{ p(θ +1 → θ)} = \frac{0.5 min ( P(θ +1)/P(θ),1 )}{ 0.5 min ( P(θ)/P(θ +1),1 )}\) =

\(\frac {1} {P(\theta)/P(\theta+1)} \)

[...] \(\frac {P(\theta)/P(\theta+1)} {1}\) (if P(\theta+1) < P(\theta))

= \(\frac{P(\theta+1)} {P(\theta)}\)

\(\frac {1} {P(\theta)/P(\theta+1)} \)

[...] \(\frac {P(\theta)/P(\theta+1)} {1}\) (if P(\theta+1) < P(\theta))

= \(\frac{P(\theta+1)} {P(\theta)}\)

Answer

(if P(\theta+1) > P(\theta))

status | not learned | measured difficulty | 37% [default] | last interval [days] | |||
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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

scheduled repetition interval | last repetition or drill |

The ratio of the transition probabilities is \(\frac{p(θ → θ +1)}{ p(θ +1 → θ)} = \frac{0.5 min ( P(θ +1)/P(θ),1 )}{ 0.5 min ( P(θ)/P(θ +1),1 )}\) = \(\frac {1} {P(\theta)/P(\theta+1)} \) (if P(\theta+1) > P(\theta)) \(\frac {P(\theta)/P(\theta+1)} {1}\) (if P(\theta+1) < P(\theta)) = \(\frac{P(\theta+1)} {P(\theta)}\)

Tags

#bayes #programming #r #statistics

Question

The ratio of the transition probabilities is \(\frac{p(θ → θ +1)}{ p(θ +1 → θ)} = \frac{0.5 min ( P(θ +1)/P(θ),1 )}{ 0.5 min ( P(θ)/P(θ +1),1 )}\) =

\(\frac {1} {P(\theta)/P(\theta+1)} \) (if P(\theta+1) > P(\theta))

[...] (if P(\theta+1) < P(\theta))

= \(\frac{P(\theta+1)} {P(\theta)}\)

\(\frac {1} {P(\theta)/P(\theta+1)} \) (if P(\theta+1) > P(\theta))

[...] (if P(\theta+1) < P(\theta))

= \(\frac{P(\theta+1)} {P(\theta)}\)

Answer

\(\frac {P(\theta)/P(\theta+1)} {1}\)

status | not learned | measured difficulty | 37% [default] | last interval [days] | |||
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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

scheduled repetition interval | last repetition or drill |

>The ratio of the transition probabilities is \(\frac{p(θ → θ +1)}{ p(θ +1 → θ)} = \frac{0.5 min ( P(θ +1)/P(θ),1 )}{ 0.5 min ( P(θ)/P(θ +1),1 )}\) = \(\frac {1} {P(\theta)/P(\theta+1)} \) (if P(\theta+1) > P(\theta)) \(\frac {P(\theta)/P(\theta+1)} {1}\) (if P(\theta+1) < P(\theta)) = \(\frac{P(\theta+1)} {P(\theta)}\) <span><body><html>

Tags

#bayes #programming #r #statistics

Question

The ratio of the transition probabilities is \(\frac{p(θ → θ +1)}{ p(θ +1 → θ)} = \frac{0.5 min ( P(θ +1)/P(θ),1 )}{ 0.5 min ( P(θ)/P(θ +1),1 )}\) =

\(\frac {1} {P(\theta)/P(\theta+1)} \) (if P(\theta+1) > P(\theta))

\(\frac {P(\theta)/P(\theta+1)} {1}\)

[...]

= \(\frac{P(\theta+1)} {P(\theta)}\)

\(\frac {1} {P(\theta)/P(\theta+1)} \) (if P(\theta+1) > P(\theta))

\(\frac {P(\theta)/P(\theta+1)} {1}\)

[...]

= \(\frac{P(\theta+1)} {P(\theta)}\)

Answer

(if P(\theta+1) < P(\theta))

status | not learned | measured difficulty | 37% [default] | last interval [days] | |||
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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

scheduled repetition interval | last repetition or drill |

abilities is \(\frac{p(θ → θ +1)}{ p(θ +1 → θ)} = \frac{0.5 min ( P(θ +1)/P(θ),1 )}{ 0.5 min ( P(θ)/P(θ +1),1 )}\) = \(\frac {1} {P(\theta)/P(\theta+1)} \) (if P(\theta+1) > P(\theta)) \(\frac {P(\theta)/P(\theta+1)} {1}\) <span>(if P(\theta+1) < P(\theta)) = \(\frac{P(\theta+1)} {P(\theta)}\) <span><body><html>

Tags

#bayes #programming #r #statistics

Question

The ratio of the transition probabilities is \(\frac{p(θ → θ +1)}{ p(θ +1 → θ)} = \frac{0.5 min ( P(θ +1)/P(θ),1 )}{ 0.5 min ( P(θ)/P(θ +1),1 )}\) =

\(\frac {1} {P(\theta)/P(\theta+1)} \) (if P(\theta+1) > P(\theta))

\(\frac {P(\theta)/P(\theta+1)} {1}\) (if P(\theta+1) < P(\theta))

=

[...]

\(\frac {1} {P(\theta)/P(\theta+1)} \) (if P(\theta+1) > P(\theta))

\(\frac {P(\theta)/P(\theta+1)} {1}\) (if P(\theta+1) < P(\theta))

=

[...]

Answer

\(\frac{P(\theta+1)} {P(\theta)}\)

status | not learned | measured difficulty | 37% [default] | last interval [days] | |||
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repetition number in this series | 0 | memorised on | scheduled repetition | ||||

scheduled repetition interval | last repetition or drill |

)} = \frac{0.5 min ( P(θ +1)/P(θ),1 )}{ 0.5 min ( P(θ)/P(θ +1),1 )}\) = \(\frac {1} {P(\theta)/P(\theta+1)} \) (if P(\theta+1) > P(\theta)) \(\frac {P(\theta)/P(\theta+1)} {1}\) (if P(\theta+1) < P(\theta)) = <span>\(\frac{P(\theta+1)} {P(\theta)}\) <span><body><html>